f(x)=cos(2x-π/3)+sin(2x-3π/2)=(1/2)cos2x+(√3/2)sin2x+cos2x=(3/2)cos2x+(√3/2)sin2x=√3sin(2x+π/3),∴f(x)的最小正周期=π,2x+π/3=kπ,k∈Z,x=(k/2-1/6)π,对称中心为((k/2-1/6)π,0).