解:|OP|=√(x²+2)∴由三角函数定义可知cosa=x/√(x²+2)=[(√3)x]/6解得x=±√10tana-sina=(-√2/x)-[-√2/√(x²+2)]=√(1/6)±√(1/5)=(√6/6)±(√5/5)
http://zhidao.baidu.com/link?url=Oqzqc4dH88XLCg937p-JrgCrPU8ue10Qhzzv_5KPBgZY1TSKnqz-kIkMD0U_CT3cR9wTatt_KmdqZMW2V53hL_
1.141,也就是:根号2
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