(x+2)-(x+20%x)=4解：去括号，得x+2-x-0.2x=4移项，得x-x-0.2x=4-2合并同类项，得-0.2x=2系数化为1，得x=-10
(x+2)-(x+20%x)=4x+2-x-0.2x=40.2x=2-40.2x=-2x=-2÷0.2x=-10
(x+2)-(x+20%x)=4x+2-1.2x=42-0.2x=40.2x=-2x=-0.1
