原式=[(2a+1)/(2a-1)]÷{[1÷(1-1/2a)^2]÷[(2a+1-1)/(2a+1)]}
=[(2a+1)/(2a-1)]÷{1÷[(2a-1)/2a]^2}÷[2a/(2a+1)]
=[(2a+1)/(2a-1)]÷{[4a^2/(2a-1)^2]÷[2a/(2a+1)]}
=[(2a+1)/(2a-1)]÷[4a^2(2a+1)/(2a-1)^2*2a]
=[(2a+1)/(2a-1)]÷[a(2a+1)/(2a-1)^2]
=(2a+1)(2a-1)^2/[(2a-1)a(2a+1)]
=(2a-1)/a
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