| (1)如图所示,每个钩码的质量为50g,重力为G=mg=0.05kg×10N/kg=0.5N,杠杆上每小格的长度假设为1cm, 则F A =0.5N×2=1N,L A =1cm×2=2cm,F B =0.5N,L B =1cm×4=4cm; ∴F A ×L A =F B ×L B (2)在A、B两处再各加挂一个50g的钩码后,F A ′=0.5N×3=1.5N,F B ′=0.5N×2=1N,L A 和L B 的长度都不变, 则F A ′×L A =1.5N×2cm=3N?cm,F B ′×L B =1N×4cm=4N?cm ∵F A ′×L A <F B ′×L B ∴杠杆右边下倾 故选C. |