答：x-y=2x=y+2代入2/x+1/y=1得：2/(y+2)+1/y=1两边同乘以(y+2)y得：2y+y+2=(y+2)y3y+2=y^2+2yy^2-y-2=0(y-2)(y+1)=0解得：y=-1或者y=2代入x=y+2得：x=1或者x=4所以：x=1,y=-1或者x=4,y=2经检验,上式两组解都是原分...
