∫(x^5+x^4-8)dx/(x^3-x) = ∫[x^2+x+1+(x^2+x-8)/(x^3-x)]dx = ∫[x^2+x+1+8/x-3/(x-1)-4/(x+1)]dx = x^3/3+x^2/2+x+8ln|x|-3ln|x-1|-4ln|x+1| + C
