2a+3ab+2b
=2a+2b+3ab
=2(a+b)+3ab
=2*4+3*1
=11
a³-a²b+a²b²+a²b-a²b²+b³
解原式=a³+b³
= -3³+2³
= -27+8
= -19
ab=1,
a=1/b,
a+b=1/b+b=4
1+b^2=4b
b=根号3+2 或b=-根号3+2
a=2-根号3 或a=2+根号3
第一题:11
第二题:-19
a+b=4 ab=1 2a+3ab+2b=2(a+b)+3ab=2*4+3*1=11
a^3-a^2*b+(ab)^2+a^2*b-(ab)^2+b^3=a^3+b^3=(-3)^3+2^3=-27+8=-19
2a+3ab+2b=2(a+b)+3ab=2×4+3×1=11
a^3-a^2*b+(ab)^2+a^2*b-(ab)^2+b^3=a^3-b^3=(-3)^3+2^3=35