1.(x^2+x)/(x^2-1)=x(x+1)/(x-1)(x+1)=x/(x-1)
2.(x^2-9)/(x^2-6x+9)
=(x-3)(x+3)/(x-3)²
=(x+3)/(x-3)
3.(x^2-8x+16)/(x^2-16)
=(x-4)²/(x+4)(x-4)
=(x-4)/(x+4)
=(5-4)/(5+1)
=1/9
1.原式=[x(x+1)]/[(x+1)(x-1)]=x/(x-1)
2.原式=[(x+3)(x-3)]/(x-3)²=(x+3)/(x-3)
3.原式=(x-4)²/[(x+4)(x-4)]=(x-4)/(x+4)=(5-4)/(5+4)=1/9
答案如图所示,因式分解就好了