解:x/x-1-1=m/(x-1)(x+2)增根∴x-1=0x+2=0∴x1=1x2=-2.两边同乘(x-1)(x+2)原程化x(x+2)-(x-1)(x+2)=m整理m=x+2x=1m=1+2=3;x=-2m=-2+2=0m=0式程变形x/x-1-1=0x=-2立前矛盾故m=0舍即m值3
