解：z=i+2/i+3/i^2+4/i^3=i+2i/i^2-3+4i/i^4=i-2i-3+4i=-3+3i|z|=√[(-3)^2+3^2]=3√2故答案为B 望采纳，若不懂，请追问。PS : i^4=(i^2)^2=(-1)^2=1
Bz=i+2i/(i^2)-3-4i/(i^2)=-3+3i所以|z|=3√2
