弧长是C=15.7cm,弧高是H=1.55cm,请问怎么样求这个圆的直径D是多少?弧半径为R.Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*RnR0=15R1=17.892R2=19.342R3=19.607R4=19.614R5=19.614R=19.614cm D=2*R=2*...
