CaCO3(s)====CaO(s)+CO2(g)
100/178=500/x ;x=890KJ
C(s)+O2(g)==点燃==CO2(g)
0.012 /393.5=y/890 ;y=0.027Kg
1吨 = 1000000克所以1吨CaCO3就是1000000克CaCO3,也就是10000 molCaCO3这些CaCO3分解需要吸热(10000/0.5)*39 = 780000(KJ)所以需要 (780000/393.5)*12 = 23786.53 (g) C(s)也就是23.78653Kg
27.14
1358
ss