x+3y=2k+1 (1)2x-y=k+3 (2)(1)+(2)×3x+3y+6x-3y=2k+1+3k+97x=5k+10x=(5k+10)/7x>0所以(5k+10)/7>05k+10>0k>-22x-y=k+3y=2x-k-3>0所以2x>k+3x>(k+3)/2所以(5k+10)/7>(k+3)/2两边乘1410k+20>7k+213k>-1k>-1/3所以k>-1/3