sinα、cosα是关于x的方程x^2-kx+k^2-3/2=0的两实根∴sinα+cosα=ksinαcosα=k^2-3/2∴1=(sinα)^2+(cosα)^2=(sinα+cosα)^2-2sinαcosα=3-k^2∴k=±√2∵3π<α<7π/2∴sinα<0,cosα<0∴k=-√2cos(3π+α)+sin(π+α)=-cosα-sinα=-(sinα+cosα)=-k=√2
sina+cosa=k,sina*cosa=k^2-3/2,yu