设速度V1 V2（假设V1比V2快）得方程组 t1*(V1-V2)=8 t2*(V1+V2)=8解得V1=8t1+8t2/t1t2 V2=8t1-8t2/t1t2所以V1/V2=(t1+t2)/(t1-t2)
