1.f(x)=cosx·sin(x+π/3)-√3cos²x+√3/4=sinxcosxcosπ/3+cos²xsinπ/3-√3cos²x+√3/4=1/4sin2x+√3/4cos2x=1/2[sin2xcosπ/3+sinπ/3cos2x)]=1/2sin(2x+π/3)f(x)的最小正周期:T=2π/2=π