f(a,b,c)=Sum_{i=1->N}{y(i)-a-b[x(i)]^2
-
c[x(i)]^(-2)}^2
0=df(a,b,c)/da
=
2Sum_{i=1->N}{y(i)-a-b[x(i)]^2
-
c[x(i)]^(-2)}(-1)
...
(1)
0=df(a,b,c)/db
=
2Sum_{i=1->N}{y(i)-a-b[x(i)]^2
-
c[x(i)]^(-2)}{-[x(i)]^2}
...
(2)
0=df(a,b,c)/dc
=
2Sum_{i=1->N}{y(i)-a-b[x(i)]^2
-
c[x(i)]^(-2)}{-[x(i)]^(-2)}
...
(3)
解由
(1),
(2),
(3)构成的关于a,b,c的三元一次方程组就可以求得a,b,c的值.