令t=x²-5x+5=(x-5/2)²-5/4故:t≥-5/4故:f[g(x)]=f(t)=-t²-t=-(t+1/2)²+1/4,对称轴t=-1/2结合图像在t≥-5/4时,f[g(x)]=f(t)=-t²-t=-(t+1/2)²+1/4取得最大值1/4故:f[g(x)]的值域为(-∞,1/4)