解:∵a与2b互为倒数∴a*2b=1∵-c与2分之b互为相反数∴-c+b/2=0∵|x|=3∴x=3，x=-3x/(2ab-2c+d+3)=3/(1+0+3)=3/4x/(2ab-2c+d+3)=-3/(1+0+3)=-3/4
由题可知2ab=1b/2=cx=±3x/(2ab-2c+d+3)=±3/(1-b+d+3)题目中没给d，猜你是把b写成d了=±3/4
