（1）kx＞2x＜0时：x＜2/kk=0时：无解k＞0时：x＞2/k(2)kx+x＜k²-2(k+1)x＜k²-2∵ 解为x＞-1/2∴k+1＜0并且(k²-2)/(k+1)=-1/2∴k＜-1并且2k²+k-3=0∴k＜-1并且(k+3)(2k-1)=0∴k=-3
