∵z=
=
+i
3
(1?
i)2
3
=
+i
3
1?2
i?3
3
=
+i
3
?2?2
i
3
=-(
+i)(?2+2
3
i)
3
(?2?2
i)(?2+2
3
i)
3
+
3
4
i.1 4
∴
=1 z
=4 ?
+i
3
=?4(?
?i)
3
(?
+i)(?
3
?i)
3
?i
3
∴|
|=|?1 z
?i|=2
3
故选项为D