y=x^2×sin(1/x) 根据求导公式可得：y'=2x×sin(1/x)+[x^2×cos(1/x)×(-1/x^2)] (注：依据两个求导公式：①若y=f1(x)f2(x),则有y'=f1'(x)f2(x)+f2'(x)f1(x);②若y=f(g(x)),则y'=f'(g(x))×g'(x)).
