a+b=3+2根号2+3-2根号2=6ab=(3+2根号2)(3-2根号2)平方差=9-8=1所以原式=ab(a+b)=1*6=6
a^2b+ab^2的值为6，解答如下：a^2b+ab^2=ab(a+b)=(3+2√2)(3-2√2)(3+2√2+3-2√2)=（9-8）x6=6
