y=(LOG4x)^2+LOG2x^2+1=2LOG(2*2x)+2LOG(2*x)+1=2LOG2+2LOG(2*x)+2LOG2+2LOGx+1=6LOG2+4LOGx+1因为LOGx在(0,+∞)上单调递增,x∈[1/4,2],所以当x=2时,y有最大值为10LOG2+1;当x=1/4时,y=6LOG2+4LOG(1/4)+1=6LOG2-4L...