x²-2x+1/x²+x ÷(1- 2/x+1),其中x=√3解：x²-2x+1/x²+x ÷(1- 2/x+1)=(x-1)²/[x(x+1)] ÷ (x+1-2)/(x+1)=(x-1)²/[x(x+1)] × (x+1)/(x-1)=(x-1)/x当x=√3,原式＝(x-1)/x=(√3-1)/√3=(3-√3)/3
