f(x)=2x^3+3x^2-6x+1
f(1)=0
2x^3+3x^2-6x+1 =(x-1)(2x^2+ax-1)
coef. of x
-1-a=-6
a=5
2x^3+3x^2-6x+1
=(x-1)(2x^2+5x-1)
=(x-1)(2x^2+5x-1)
=2(x-1)(x^2+(5/2)x-1/2)
=2(x-1)[x-(-5+√33)/4].[x-(-5-√33)/4]
2x^3+3x^2-6x+1 =(x-1)(2x^2+5x-1).
2x³+3x²-6x+1
=2x³-2+3(x²-2x+1)
=2(x-1)(x²+x+1)+3(x-1)²
=(x-1)(2x²+2x+2+3x-3)
=(x-1)(2x²+5x-1)
=(x-1)(x-x1)(x-x2)
其中x1，x2是方程2x²+5x-1的两根。
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