(1+sin4α-cos4α) /(1+sin4α+cos4α)=(sin^2(2α)+cos^2(2α)+2sin2αcos2α-cos^2(2α)+sin^2(2α))/(sin^2(2α)+cos^2(2α)+2sin2αcos2α+cos^2(2α)-sin^2(2α))=[2sin^2(2α)+2sin2αcos2α]/[2cos^2(2α)+2s...
