设它的首项为a1,公比为q 前3项和是-3/5 则a1(1-q^3)/(1-q)=-3/5 (1) 前6项的和是21/5 则a1(1-q^6)/(1-q)=21/5 (2) (2)/(1) 1+q^3=-7 q^3=-8 q=-2 代入(1) a1=-1/5 它的前10项的和S10=a1(1-q^10)/(1-q) =(-1/5)*[1-(-2)^10]/(1+2) =(1/15)(2^10-1) =(2^10-1)/15 =1023/15