答：5/(x²+3x) -1/(x²-x)=05/(x²+3x)=1/(x²-x)5(x²-x)=x²+3x5x²-5x-x²-3x=04x²-8x=0x=0或者x=2经检验，x=0是增根所以：原分式方程的根为x=2
