∫u/(u+1)²du
=∫u/(u+1)²d(u+1)
=-∫ud[1/(u+1)]
=-u/(u+1)+∫[1/(u+1)]d(u+1)
=-u/(u+1)+ln|u+1|+C
∫udu/(u+1)² = ∫(u+1-1)du/(u+1)²= ∫[1/(u+1)-1/(u+1)²]du
= ln|u+1| +1/(u+1) + C
∫ u/(u+1)^2 du
=-∫ u d[1/(u+1)]
=-u/(u+1) +∫ du/(u+1)
=-u/(u+1) +ln|u+1| + C
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