∫1/√(2-3x^2) dx令x =√(2/3) sinudx = √(2/3) cosu du√(2-3x^2) = √[2-2(sinu)^2] = √2 cosu∫1/√(2-3x^2) dx=∫√(2/3) cosudu/(√2 cosu) =(1/√3)∫du= (1/√3) u+ C=(1/√3) arcsin(√3x/√2) + C...
