当电键S1断开、S2闭合时,电阻R2和R3被短路,则有电源输出功率P0=( E R+r )2R当S1闭合、S2断开时,电阻R1和R2被短路,则有电源输出功率P0=( E 4R+r )2?4R联立解得,E=3 P0R ,r=2R当S1、S2都断开时,电源的总功率为P=EI= E2 R1+R2+R3+r = (3 P0R )2 7R+2R =P0.故答案为:3 P0R ,P0