过D作DH丄AC,垂足为点H由DH丄AC,DF丄AB,AD是三角形ABC的角平分线,知三角形ADF与ADH全等,DF=DH由DH丄AC,DF丄AB,DF=DH,DE=DG,知三角形DEF与DGH全等,即S(DEF)=S(DGH)又50=S(ADG)=S(DGH)+S(ADH)=S(DEF)+S(ADF)=S(DEF)+(S(DEF)+S(AED))=2S(DEF)+S(AED)=2S(DEF)+39故S(DEF)=11/2=5.5答案B