设x4+mx3+nx-16=(x-1)(x-2)(x2+ax+b)=(x2-3x+2)(x2+ax+b) 得 2b=-16 b-3a+2=0 b=-8 a=-2 (x-1)(x-2)(x2-2x-8)=(x-1)(x-2)(x-4)(x+2)=x4-5x3+20x-16 m=-5 n=20
