f(x)=4sin(x-π/3)cosx+√3 =4sinxcosπ/3cosx-4cosxsinπ/3cosx+√3 =sin2x-√3(cos2x+1)+√3 =sin2x-√3cos2x =2(1/2sin2x-√3/2cos2x) =2sin(2x-π/3) T=2π/2=π
