f（x）=4x6+3x5+4x4+2x3+5x2-7x+9=（4x5+3x4+4x3+2x2+5x-7）x+9=[（4x4+3x3+4x2+2x+5）x+8]+1={{{[（4x+3）x+4]x+2}x+5}x-7}x+9∴在x=4时的值时，V3的值为[（4x+3）x+4]x+2=[（4×4+3）×4+4]×4+2=322故选A．
