(sinx*cosx)⼀(cosx+1+sinx)化简

2026年09月17日 23:07
有1个网友回答
网友(1):

(sinx*cosx)/(cosx+1+sinx)
=1/2[1+2sinx*cosx-1]/(cosx+1+sinx)
=1/2[(cosx+sinx)^2-1]/(cosx+sinx+1)
=1/2[(cosx+sinx+1)(cosx+sinx-1)]/(cosx+sinx+1)
=1/2(cosx+sinx-1)
=√2/2(√2/2cosx+√2/2sinx)-1/2
=√2/2sin(x+π/4)-1/2