用递等式计算.(1)2184-[(44×19+44)÷5](2)(2.5-2.5×0.6)÷0.25(3) ( 4 5 + 1

用递等式计算.(1)2184-[(44×19+44)÷5](2)(2.5-2.5×0.6)÷0.25(3) ( 4 5 + 1 4 )÷ 7 5 + 5 6 (4) 1 5 ÷[( 2 3 + 1 5 )× 1 13 ] .
2026年09月24日 19:19
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(1)2184-[(44×19+44)÷5],
=2184-[(19+1)×44÷5],
=2184-[20×44÷5],
=2184-[880÷5],
=2184-176,
=2008;

(2)(2.5-2.5×0.6)÷0.25,
=[2.5×(1-0.6)]÷0.25,
=[2.5×0.4]÷0.25,
=1÷0.25,
=4;

(3) (
4
5
+
1
4
)÷
7
5
+
5
6
,
=
21
20
×
5
7
+
5
6
,
=
3
4
+
5
6
,
=
19
12
;

(4)
1
5
÷[(
2
3
+
1
5
)×
1
13
]
,
=
1
5
÷[
13
15
×
1
13
],
=
1
5
÷
1
15
,
=3.