答案为：{x|1＜x＜4，x≠3}。具体步骤如下：由2/(x-3)+3＞x+1可知，x≠3；2/(x-3)+3＞x+12/(x-3)＞x+1-32＞(x-2)(x-3)x²-5x+6＜2x²-5x+4＜0△=25-16=9＞0x∈(1,4),x≠31-3(x+1)≤8-x3(x+1)≥x-72x≥-10x∈(-5,正无穷)综上所述，{x|1＜x＜4，x≠3}
