首先可验证恒等式a^3+b^3+c^3-3abc = (a+b+c)(a^2+b^2+c^2-ab-bc-ca).代入a+b+c = a^3+b^3+c^3 = 0得abc = 0.于是a^5+b^5+c^5 = (a+b+c)(a^4+b^4+c^4)-(ab^4+ac^4+ba^4+bc^4+ca^4+cb^4)= (a+b+c)(a^4+b^4+c^4)-(ab+bc+ca)(a^3+b^3+c^3)+abc(a^2+b^2+c^2)= 0.