数学归纳法证明证明,n^(n+1)>,若成立,则有（n^(n+1)）/n^(n+1)〉1[n/(n+1)]^n*n>1当n=3时,[3/4]^3*3=81/64>1,不等式成立设档n=k时成立,即,[k/(k+1)]^k*k>1则在n=k+1,时,[(k+1)/(k+2)]^(k+1)*(k+1)=[(k+1)/(k+2)]^k*[...
