请看图：
∫xdx/(x^3-3x+2)=ʃxdx/[(x-1)(x-2)]=ʃx[1/(x-2)-1/(x-1)]dx=ʃ[x/(x-2)-x/(x-1)]dx=ʃ[2/(x-2)-1/(x-1)]dx=2ʃd(x-2)/(x-2)-ʃd(x-1)/(x-1)=2ln|x-2|-ln|x-1|+C
