分解因式x²-xy+xz-yz=x(x-y)+z(x-y)=(x-y)(x+z)
解：原式=(x²-xy)+(xz-yz) =x(x-y)+z(x-y) =(x+z)(x-y)希望对你有帮助(^_^)
x²-xy+xz-yz=x(x-y)+z(x-y)=(x-y)(x+z)
（X+Z）(X-Y)
