原方程可化为1/(x+2)(x-1) +1/(x+2)(x+5) ＝2即[1/(x-1) - 1/(x+2)]/3+ [1/(x+2) -1/(x+5)]/3＝2即1/(x-1) -1/(x+5)＝6即6(x-1)(x+5)＝6即x²+4x-5＝1即x²+4x-6＝0解得x＝-2±√10
X1=2 X2=-4（不知道对不对~）
