解：原式=(x+3)/(2x-4)÷[5/(x-2)-x-2]=(x+3)/[2(x-2)]÷[5/(x-2)-(x+2)(x-2)/(x-2)]=(x+3)/[2(x-2)]÷{[(5-(x²-4)]/(x-2)}=(x+3)/[2(x-2)]÷[-(x²-9)/(x-2)]=(x+3)/[2(x-2)]×[-(x-2)/(x+3)(x-3)]= -1/[2(x-3)]O(∩_∩)O欢迎采纳，不懂可追问！
