解由y-(y²-2)/(2y-3)≥0得y(2y-3)/(2y-3)-(y²-2)/(2y-3)≥0即(2y^2-3y)/(2y-3)-(y²-2)/(2y-3)≥0得[(2y^2-3y)-(y²-2)]/(2y-3)≥0即(y²-3y+2)/(2y-3)≥0
