f(x+1)=x2-4令x+1=tx=t-1f(t)=(t-1)²-4=t²-2t-3令t=x-1所以f(x-1)=(x-1)²-2(x-1)-3=x²-2x+1-2x+2-3=x²-4x
令x+1=t,则x=t-1f(t)=(t-1)²-4再令t=x-1,f(x-1)=(x-1-1)²-4=x²-4x+4-4即f(x-1)=x²-4x
令a-1=x+1则x=a-2所以f(a-1)=(a-2)²-4=a²-4a所以f(x-1)=x²-4x