⊙01ρ=4cosθρ²=4ρcosθx²+y²=4x-------(1)(x-2)²+y²=4⊙02ρ=-4sinθρ²=-4ρsinθx²+y²=-4y------(2)x²+(y+2)²=4(1)(2)联立x=-y经过⊙01,⊙02交点的直线的直角坐标方程y=-x