2+(n-1)×2的n+1次方
Sn=1·2^1+2·2^2+3·2^3+……+n·2^n2Sn=1·2^2+2·2^3+……+(n-1)·2^n+n·2^(n+1)∴Sn=2Sn-Sn=-2^1-2^2-2^3-……-2^n+n·2^(n+1) =-(2^(n+1)-2)+n·2^(n+1) =(n-1)·2^(n+1)+2